14x^2+56x-1334=0

Solution for 14x^2+56x-1334=0 equation:

14x^2+56x-1334=0

a = 14; b = 56; c = -1334;
Δ = b2-4ac
Δ = 562-4·14·(-1334)
Δ = 77840
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{77840}=\sqrt{16*4865}=\sqrt{16}*\sqrt{4865}=4\sqrt{4865}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(56)-4\sqrt{4865}}{2*14}=\frac{-56-4\sqrt{4865}}{28}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(56)+4\sqrt{4865}}{2*14}=\frac{-56+4\sqrt{4865}}{28}
$